Evaluate . Which conclusion is correct?
Limits & Limit Notation Assessment
31 questions · 31 parts · 98.00000000200001 marks
Questions
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Find limx→0−1/x. Which conclusion is correct?
Evaluate limx→3(2x+1). Which conclusion is correct?
Before attempting worked case A, which statement correctly records the condition that makes limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L usable?
Use limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L to write the first valid mathematical step for case A: Evaluate limx→2x−2x2−4.
Carry out the essential calculation for case B: Find limx→0−1/x. Show at least one meaningful line before the conclusion.
For case C, Evaluate limx→3(2x+1). Give the conclusion and one sentence explaining why it follows.
working sort the statements about case A into “supports a valid solution” and “does not support a valid solution”. Case A is: Evaluate limx→2x−2x2−4.
Solve case A completely: Evaluate limx→2x−2x2−4. State the relationship or method, show the calculation, then check the condition.
Solve case B completely: Find limx→0−1/x. Keep the key assumption, restriction, or algorithm rule visible in your working.
Solve case C completely: Evaluate limx→3(2x+1). Include an exact form, interval, unit, or interpretation whenever the task needs one.
A learner reports “Factor: (x−2)(x+2)/(x−2), so the limit is 4.” for case A but gives no justification. Which addition makes the response mathematically defensible?
For the three lesson cases below, sort each statement as a “direct conclusion”, a “required check”, or “not justified by the stated mathematics”.
Put a defensible solution path for case A in order. The case is: Evaluate limx→2x−2x2−4.
- 1.ACarry out the calculation or construction for case A
- 2.BState the checked conclusion: Factor: (x−2)(x+2)/(x−2), so the limit is 4.
- 3.CRead and identify the target in case A
- 4.DRecord the condition: A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero.
- 5.EChoose the relationship or algorithm: limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L
Put a defensible solution path for case B in order. The case is: Find limx→0−1/x.
- 1.AState the checked conclusion: −∞.
- 2.BRead and identify the target in case B
- 3.CRecord the condition: A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero.
- 4.DChoose the relationship or algorithm: limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L
- 5.ECarry out the calculation or construction for case B
Compare the three distinct Limits & Limit Notation cases in three labelled mini-responses: A (Evaluate limx→2x−2x2−4.), B (Find limx→0−1/x.), and C (Evaluate limx→3(2x+1).). For each, state the representation or first step, the conclusion, and one check; use mathematics rather than a general study tip.
A student begins case B — Find limx→0−1/x. — by treating this as optional: “A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero.”. Diagnose the mathematical problem and repair the first two lines of the solution.
Solve case B (Find limx→0−1/x.); Check the method against limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L and A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero. Write a complete solution, including one check that could expose an error.
The lesson requires you to: Express and interpret limits using correct notation and estimate limits from graphs and tables. Use case C (Evaluate limx→3(2x+1).) to explain how the relationship limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L makes that capability possible.
For each case, give the first mathematical step and conclusion/check: (A: Evaluate limx→2x−2x2−4.; (B: Find limx→0−1/x.; (C: Evaluate limx→3(2x+1).) in Limits & Limit Notation.
For case C — Evaluate limx→3(2x+1). — which starting representation or method is best aligned with this lesson?
Analyse the boundary of case A: Evaluate limx→2x−2x2−4. Keep its mathematical structure, then specify one changed value, sign, interval, or algorithm decision that would make the condition “A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero.” fail. Decide with working whether the original conclusion Factor: (x−2)(x+2)/(x−2), so the limit is 4. still follows.
starting from case B — Find limx→0−1/x. — create one fully specified new numerical or symbolic instance of the same Limits & Limit Notation structure. Solve it, check A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero., and explain how its conclusion compares with −∞.
Write a proof-quality validation of case C: Evaluate limx→3(2x+1). Your answer must show why Direct substitution gives 7. follows from limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L, identify a tempting invalid move, and use A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero. to rule it out.
Create an annotated canvas solution for case A: Evaluate limx→2x−2x2−4. Show the governing relationship, each key calculation or construction, the condition, and the checked conclusion.
Create an annotated canvas solution for case B: Find limx→0−1/x. Use a diagram, graph, equation layout, table, or algorithm trace only where it clarifies the specific mathematics.
Create an annotated canvas solution for case C: Evaluate limx→3(2x+1). Make the exact answer, interval, unit, direction, or interpretation visible where the case requires it.
The later lesson capability is: Determine limits using algebraic properties of limits and algebraic manipulation. Compare cases A and B (Evaluate limx→2x−2x2−4.; Find limx→0−1/x.) and decide which case better demonstrates that capability. Support your decision using both actual conclusions (Factor: (x−2)(x+2)/(x−2), so the limit is 4.; −∞.) and the condition A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero.
Act as an examiner auditing three candidate claims about Limits & Limit Notation. Sort them into “earns credit”, “earns partial credit only”, and “does not earn credit”; use the concrete worked cases and the stated condition.
build and solve a four-stage Limits & Limit Notation problem that deliberately combines the lesson ideas in cases A, B, and C. Use precise values or symbolic data, state how it addresses “Determine limits using the squeeze theorem and select an appropriate procedure for a given limit.”, apply limx→af(x)=L⟺limx→a−f(x)=limx→a+f(x)=L, and end by checking A two-sided limit does not exist when the one-sided limits differ. Do not cancel a factor before noting that the original expression was undefined at its zero.
Evaluate limx→−∞x3−5x3x3+2.