1.Lesson overview

Syllabus focus
Cambridge IAL syllabus reference
  • 1.1 Particles in the atom and atomic radius
  • 1.2 Isotopes
Edexcel IAL syllabus reference
  • Sub-atomic particles, isotopes and atomic notation (2.1–2.5)
  • Mass spectrometry (2.6–2.7)
  • Ionisation energies and evidence for shells and sub-shells (2.8, 2.10–2.11)
  • Orbitals and electronic configuration (2.9, 2.12–2.16)
  • Periodicity of physical properties (2.17–2.18)
  • 3A Ionic bonding
AQA IAL syllabus reference
  • 1.1 Atomic structure (International AS)
AP Chemistry syllabus reference
  • 1.2 Mass Spectra of Elements
  • 1.7 Periodic Trends
By the end of this lesson you should be able to
  • Describe the relative charge, relative mass and location of protons, neutrons and electrons in an atom.
  • Use atomic number, mass number, nuclide notation and ionic charge to determine the numbers of protons, neutrons and electrons in atoms and ions.
  • Define isotopes and explain why isotopes of an element have the same chemical properties but different masses and densities.
  • Interpret isotope mass-spectral peaks and calculate relative atomic mass from isotopic masses and relative abundances.
  • Explain trends in atomic and ionic radius across a period, down a group and within an isoelectronic series.

Every calculation and bonding model in chemistry begins with a disciplined picture of the atom. This chapter separates what is fixed in the nucleus from what can change when ions form, then uses isotopes and abundance data to explain why periodic-table masses are usually not whole numbers.

How this chapter fits together

Start by decoding nuclear symbols, then count particles in atoms and ions. Next distinguish isotopic mass from weighted relative atomic mass, and finally connect nuclear charge, shielding and outer-shell distance to atomic radius.

2.Key language and ideas

Use these definitions precisely
Proton
A positively charged particle in the nucleus with relative mass 1 and charge +1.
Neutron
An uncharged particle in the nucleus with relative mass 1.
Electron
A negatively charged particle outside the nucleus with negligible relative mass and charge −1.
Isotope
Atoms of the same element with the same proton number but different numbers of neutrons.
Relative atomic mass,
The weighted mean mass of an atom of an element relative to of the mass of a carbon-12 atom.
Atomic radius
Half the distance between the nuclei of two bonded atoms of the same element; it is a measured convention rather than a sharp atomic edge.

3.Read nuclear notation as a particle inventory

Write a nuclide as , where is the proton number and is the mass number. Protons determine the element: any atom with is chlorine. The neutron number is . In a neutral atom, electrons equal protons because the total charge is zero.

The symbol for lithium-7 with its mass number 7 and proton number 3 labelled, beside a nucleus of three protons and four neutrons with three electrons in shells around it.
Figure 1: The two numbers in the symbol give the protons (3) and the nucleons (7), so the neutrons are A − Z = 4 and a neutral atom has 3 electrons.

The mass number is not the periodic-table value. It applies to one isotope and is always a whole number, whereas is an abundance-weighted mean for a natural sample. Keep the labels visible in calculations: this prevents confusing 35Cl with chlorine's approximate of 35.5.

4.Nuclide notation separates charge and mass

Atomic number counts protons; mass number counts protons plus neutrons. Isotopes have the same but different neutron numbers, so neutral atoms of an element have similar electron arrangements but different masses. A positive ion has lost electrons, not protons. Relative atomic mass is an abundance-weighted mean of isotope masses, not usually a whole number. Mass-spectrometric peak heights must be interpreted as abundances under the given measurement model.

5.Separate nuclear identity from ionic charge

Ion formation changes electrons, never protons or neutrons. A positive ion has lost electrons, so minus the positive charge. A negative ion has gained electrons, so plus the magnitude of the negative charge.

For example, contains 13 protons, 14 neutrons and 10 electrons. It is still aluminium after losing three electrons because its nucleus still contains 13 protons. This distinction is essential when linking electron loss to oxidation and bonding later in the course.

Fast particle-count rules

6.Predict particle-beam deflection from charge and mass

When proton, neutron and electron beams enter the same uniform electric field at the same speed, separate direction from amount of deflection. A charged particle feels an electric force; an uncharged neutron does not. Positive and negative particles curve towards opposite plates.

Electric force
Resulting acceleration
What to say about each beam
  • A neutron travels straight because its charge is zero, so the electric field exerts no electric force on it.
  • A proton curves towards the negative plate because its charge is positive.
  • An electron curves towards the positive plate because its charge is negative.
  • An electron bends far more than a proton: their charge magnitudes are equal, but the electron has about of the proton mass.
Exam-response pattern
State the direction first, then justify the relative bend with charge-to-mass ratio. Saying only that an electron is “lighter” leaves out the force and direction marks.

7.Use isotopes to explain mass data, not chemical differences

Isotopes have nearly identical chemical properties because chemical behaviour depends mainly on the electron arrangement, which is the same for neutral isotopes of one element. Their different masses affect physical processes, including diffusion, and produce separate peaks in a mass spectrum.

A mass spectrometer turns particles into ions, separates them by mass-to-charge ratio, and detects their relative abundance. A peak at a particular value is evidence for ions of a particular isotope or molecular fragment; peak height or area represents relative abundance, not necessarily a count of atoms in one molecule.

8.Calculate a weighted mean relative atomic mass

A sample with more of a heavy isotope has a larger . Multiply each isotopic mass by its fractional abundance, add the contributions, and round only at the end. When abundances are percentages, either divide each by 100 first or divide the final sum by 100.

Chlorine-35 and chlorine-37 atoms with identical electron shells of 2, 8, 7; 75% of natural chlorine is chlorine-35 and 25% is chlorine-37, and their weighted average is 35.5.
Figure 2: Multiplying each isotope's mass by its abundance and dividing by 100 gives 35.5, a value between 35 and 37 and closer to the more abundant chlorine-35.

The result should lie between the lightest and heaviest isotopic masses and closer to the more abundant isotope. That simple estimate is a powerful error check before committing to a final answer.

Weighted-mean relationship

9.Explain atomic radius with attraction and distance

Across a period, atomic radius generally decreases. Proton number rises while added electrons enter the same principal shell, so shielding changes little and the stronger nuclear attraction pulls the outer electrons closer. Down a group, radius increases because an additional occupied shell places the outer electrons farther from the nucleus and increases shielding.

Do not describe radius as depending only on proton number. A large nuclear charge can be outweighed by extra shells and shielding. Compare species fairly: a set of isoelectronic ions has the same number of electrons, so the species with more protons is smaller because the same electron cloud is pulled in more strongly.

What changes in common radius comparisons?
ComparisonDominant explanation
Across a periodNuclear charge increases while added electrons enter the same shell; stronger attraction gives a smaller atom.
Down a groupAn extra occupied shell and greater shielding place the outer electrons farther from the nucleus.
Cation compared with its atomElectron loss reduces electron-electron repulsion and may remove the outer shell, so the cation is smaller.
Anion compared with its atomElectron gain increases electron-electron repulsion while nuclear charge is unchanged, so the anion is larger.
Isoelectronic ionsMore protons pull the same number of electrons closer, producing the smaller ion.

10.Worked example: order an isoelectronic series by radius

Question

Place , , and in decreasing order of ionic radius. Explain your reasoning.

Step-by-step solution
  1. 1
    Each ion contains 18 electrons, so the ions are isoelectronic. Their electron clouds can be compared directly.
  2. 2
    The proton numbers are 16, 17, 19 and 20 respectively. Moving from to increases nuclear charge.
  3. 3
    More protons attract the same number of electrons more strongly, pulling the electron cloud closer to the nucleus.
  4. 4
    Therefore the decreasing-radius order is .
Where the marks are won
Do not use ionic charge alone as the explanation. First establish that the ions have the same electron count; then link increasing proton number to stronger attraction and a smaller radius.

11.Use mass-spectral evidence quantitatively

A mass spectrum is more than a list of isotope masses. The position of a peak gives an ion's mass-to-charge ratio, while its relative abundance gives evidence about how common that ion is in the sample. For a singly charged atomic ion, the m/z value is numerically the isotope mass. A weighted mean of the isotope masses gives the relative atomic mass printed in a Periodic Table; it is not the mass of any one atom.

The same logic extends to molecules. A diatomic molecule made from two isotopes produces more than one molecular-ion peak because different isotope pairings are possible. For chlorine, the 35Cl–35Cl, 35Cl–37Cl, and 37Cl–37Cl combinations give an approximately 9:6:1 cluster. The middle peak is twice as likely as either mixed ordering because the two atoms can occupy either position.

A disciplined way to think about it
Treat peak position and peak height as separate evidence: mass identifies a species, while abundance identifies its contribution.

12.Worked example 1: Count particles in a chloride ion

Question

State the numbers of protons, neutrons and electrons in .

Step-by-step solution
  1. 1
    The lower number, 17, is the proton number, so there are 17 protons.
  2. 2
    number − proton number = .
  3. 3
    The charge means one extra electron compared with the neutral atom: electrons.
  4. 4
    Report all three quantities with their particle names, not as an unlabelled list.
Where the marks are won
Award credit separately for 17 protons, 20 neutrons and 18 electrons. The charge alters electrons only.

13.Worked example 2: Find relative atomic mass from isotopic abundance

Question

An element has isotopes of mass 63.0 (69.2%) and 65.0 (30.8%). Calculate its .

Step-by-step solution
  1. 1
    Use a weighted mean: .
  2. 2
    Calculate the numerator: .
  3. 3
    Divide by 100 to obtain .
  4. 4
    Give an appropriate rounded value, , which is closer to 63.0 because that isotope is more abundant.
Where the marks are won
The method must weight both masses by abundance; an ordinary mean of 64.0 is not justified.

14.Worked example 3: Chlorine is 75% ³⁵Cl and 25% ³⁷Cl. Predict the relative abundances of the molecular ions Cl₂⁺ at m/z 70, 72 and 74.

Question

Chlorine is 75% ³⁵Cl and 25% ³⁷Cl. Predict the relative abundances of the molecular ions Cl₂⁺ at m/z 70, 72 and 74.

Step-by-step solution
  1. 1
    The 70 ion is ³⁵Cl–³⁵Cl, so its probability is .
  2. 2
    The 72 ion can be formed in two ways, ³⁵Cl–³⁷Cl or ³⁷Cl–³⁵Cl, so its probability is .
  3. 3
    The 74 ion is ³⁷Cl–³⁷Cl, so its probability is .
  4. 4
    Divide by the smallest value: 0.5625 : 0.375 : 0.0625 = 9 : 6 : 1.
What the method shows
The central peak must include both orders of the mixed isotope pair. Omitting one order gives 9:3:1, which is not the molecular-isotope pattern.

15.Worked example: explain beams in an electric field

Question

Beams of protons, neutrons and electrons travel at the same speed between parallel plates. The upper plate is positive and the lower plate is negative. Describe the path of each beam and explain why the electron path is the most curved.

Step-by-step solution
  1. 1
    The neutron has no charge, so it is not attracted to either plate and continues in a straight line.
  2. 2
    The proton is positive, so it curves downwards towards the negative plate.
  3. 3
    The electron is negative, so it curves upwards towards the positive plate: this is the opposite direction to the proton.
  4. 4
    The electron and proton have equal charge magnitude, but the electron has much less mass. Its charge-to-mass ratio is therefore much larger, so its acceleration and curvature are much greater.
Where the marks are won
A complete explanation names the plate, identifies the sign of charge, notes that the neutron is undeflected, and compares charge-to-mass ratio rather than mass alone.

16.Extended worked case: apply and evaluate

Problem

An element has isotopes of mass 35 (75%) and 37 (25%). Estimate its relative atomic mass.

Reasoned solution
  1. 1

    Convert percentages to fractions: 0.75 and 0.25.

  2. 2

    Weighted mean is .

  3. 3

    The result lies between the isotope masses and closer to 35 because that isotope is more abundant.

Check or limitation

Do not average 35 and 37 unweighted; the abundances are unequal.

17.Interpreting isotope evidence from mass-spectral data

A spectrum is experimental evidence for isotopic composition. Treat the supplied peak data as measurements: identify the peaks, use their relative heights or areas, and state the conclusion with suitable precision.

Interpreting isotope evidence from mass-spectral data
  1. 1
    Identify
    Stage 1
    Record each isotope's value and its relative abundance, checking whether ions are singly charged.
  2. 2
    Calculate
    Stage 2
    Use the abundance-weighted mean, retaining guard figures until the final result.
  3. 3
    Evaluate
    Stage 3
    Check that the calculated value lies between the isotope masses and compare it with the tabulated value.
Safety and quality
If a school demonstration uses an instrument, follow local radiation, high-voltage and vacuum-system procedures. In written data work, distinguish experimental resolution from a genuine extra isotope peak.

18.Connections, patterns and applications

Think beyond this page
To electron structure
The proton number fixes the electron number of a neutral atom, so it is the bridge from nuclear notation to electronic configuration.
To bonding
The radius and charge of ions help explain lattice strength, polarisation and the properties of ionic compounds.

19.Exam method: decode any nuclide before calculating

A short, labelled inventory prevents the most common ion and isotope errors.

A reliable exam method
  1. 1
    Read
    Stage 1
    Extract , and any ionic charge.
  2. 2
    Calculate
    Stage 2
    Find protons, then neutrons, then electrons separately.
  3. 3
    Sense-check
    Stage 3
    Only electrons should differ between an atom and its ion; must lie within the isotope range.

20.Common misconceptions

Avoid these errors
  • Using mass number as the number of neutrons instead of subtracting proton number.
  • Changing proton number when an atom becomes an ion.
  • Calling a weighted mean an isotope mass, or averaging isotope masses without abundance weights.

21.Exam focus and retrieval

How to earn clear, accurate marks
  • Use the terms proton number and mass number rather than vague phrases such as atomic number at the top.
  • For a radius trend, state both the factor that changes and how it changes electrostatic attraction.
  • Include units or percentage treatment clearly in abundance calculations.
Quick checks — answer without looking back
  1. 1
    What remains unchanged when becomes ?
  2. 2
    Why does chlorine have a non-integer periodic-table mass?
  3. 3
    Which is smaller: or , and why?

22.Summary

What to carry forward
  • Proton number identifies an element; mass number counts protons and neutrons in one isotope.
  • Ionic charge arises from electron transfer only.
  • Relative atomic mass is an abundance-weighted mean.
  • Atomic radius reflects nuclear attraction, shielding and outer-electron distance.
I can now…
  • Build a quantitative model of the atom, including subatomic particles, atomic and ionic radius, isotopes, and nuclide notation.
Atom Builder & Electron StructureOpen full screen

23.Curriculum alignment and applied reasoning

Detailed-note focus

This extension turns the lesson into an exam-ready sequence: identify the evidence, apply the mechanism or calculation, then state a qualified conclusion. Core outcomes revisited here include: Describe the relative charge, relative mass and location of protons, neutrons and electrons in an atom.; Use atomic number, mass number, nuclide notation and ionic charge to determine the numbers of protons, neutrons and electrons in atoms and ions.; Define isotopes and explain why isotopes of an element have the same chemical properties but different masses and densities..

Cross-course alignment
Where this lesson transfers
CourseMapped focus in this lesson
Cambridge International A Level Chemistry 97011.1 Particles in the atom and atomic radius
1.2 Isotopes
Edexcel IAL ChemistrySub-atomic particles, isotopes and atomic notation (2.1–2.5)
Mass spectrometry (2.6–2.7)
Ionisation energies and evidence for shells and sub-shells (2.8, 2.10–2.11)
Orbitals and electronic configuration (2.9, 2.12–2.16)
Periodicity of physical properties (2.17–2.18)
3A Ionic bonding
AQA International A-level Chemistry1.1 Atomic structure (International AS)
AP Chemistry1.2 Mass Spectra of Elements
1.7 Periodic Trends
Applied analysis: Isotopic-abundance calculation

Scenario: An element has isotopes of mass 63 (69%) and 65 (31%). Calculate its relative atomic mass and explain why an individual atom does not have that fractional mass.

Worked reasoning: Weighted mean:

A_r = rac{(63 imes 69) + (65 imes 31)}{100} = 63.62

Worked reasoning: . The value is a population-weighted average; each atom is one isotope with its own isotopic mass.

Exam-quality communication: Use abundance as a weighting and distinguish relative atomic mass from mass number.

Precision audit
  • Name the observation, quantity, structure or variable before interpreting it.
  • Show the causal step or calculation route; do not jump from data to a conclusion.
  • State a limitation, condition or comparison whenever the evidence cannot justify an absolute claim.