1.Lesson overview
- 1.1 Particles in the atom and atomic radius
- 1.2 Isotopes
- Sub-atomic particles, isotopes and atomic notation (2.1–2.5)
- Mass spectrometry (2.6–2.7)
- Ionisation energies and evidence for shells and sub-shells (2.8, 2.10–2.11)
- Orbitals and electronic configuration (2.9, 2.12–2.16)
- Periodicity of physical properties (2.17–2.18)
- 3A Ionic bonding
- 1.1 Atomic structure (International AS)
- 1.2 Mass Spectra of Elements
- 1.7 Periodic Trends
- Describe the relative charge, relative mass and location of protons, neutrons and electrons in an atom.
- Use atomic number, mass number, nuclide notation and ionic charge to determine the numbers of protons, neutrons and electrons in atoms and ions.
- Define isotopes and explain why isotopes of an element have the same chemical properties but different masses and densities.
- Interpret isotope mass-spectral peaks and calculate relative atomic mass from isotopic masses and relative abundances.
- Explain trends in atomic and ionic radius across a period, down a group and within an isoelectronic series.
Every calculation and bonding model in chemistry begins with a disciplined picture of the atom. This chapter separates what is fixed in the nucleus from what can change when ions form, then uses isotopes and abundance data to explain why periodic-table masses are usually not whole numbers.
Start by decoding nuclear symbols, then count particles in atoms and ions. Next distinguish isotopic mass from weighted relative atomic mass, and finally connect nuclear charge, shielding and outer-shell distance to atomic radius.
2.Key language and ideas
- Proton
- A positively charged particle in the nucleus with relative mass 1 and charge +1.
- Neutron
- An uncharged particle in the nucleus with relative mass 1.
- Electron
- A negatively charged particle outside the nucleus with negligible relative mass and charge −1.
- Isotope
- Atoms of the same element with the same proton number but different numbers of neutrons.
- Relative atomic mass,
- The weighted mean mass of an atom of an element relative to of the mass of a carbon-12 atom.
- Atomic radius
- Half the distance between the nuclei of two bonded atoms of the same element; it is a measured convention rather than a sharp atomic edge.
3.Read nuclear notation as a particle inventory
Write a nuclide as , where is the proton number and is the mass number. Protons determine the element: any atom with is chlorine. The neutron number is . In a neutral atom, electrons equal protons because the total charge is zero.
The mass number is not the periodic-table value. It applies to one isotope and is always a whole number, whereas is an abundance-weighted mean for a natural sample. Keep the labels visible in calculations: this prevents confusing 35Cl with chlorine's approximate of 35.5.
4.Nuclide notation separates charge and mass
Atomic number counts protons; mass number counts protons plus neutrons. Isotopes have the same but different neutron numbers, so neutral atoms of an element have similar electron arrangements but different masses. A positive ion has lost electrons, not protons. Relative atomic mass is an abundance-weighted mean of isotope masses, not usually a whole number. Mass-spectrometric peak heights must be interpreted as abundances under the given measurement model.
5.Separate nuclear identity from ionic charge
Ion formation changes electrons, never protons or neutrons. A positive ion has lost electrons, so minus the positive charge. A negative ion has gained electrons, so plus the magnitude of the negative charge.
For example, contains 13 protons, 14 neutrons and 10 electrons. It is still aluminium after losing three electrons because its nucleus still contains 13 protons. This distinction is essential when linking electron loss to oxidation and bonding later in the course.
6.Predict particle-beam deflection from charge and mass
When proton, neutron and electron beams enter the same uniform electric field at the same speed, separate direction from amount of deflection. A charged particle feels an electric force; an uncharged neutron does not. Positive and negative particles curve towards opposite plates.
- A neutron travels straight because its charge is zero, so the electric field exerts no electric force on it.
- A proton curves towards the negative plate because its charge is positive.
- An electron curves towards the positive plate because its charge is negative.
- An electron bends far more than a proton: their charge magnitudes are equal, but the electron has about of the proton mass.
7.Use isotopes to explain mass data, not chemical differences
Isotopes have nearly identical chemical properties because chemical behaviour depends mainly on the electron arrangement, which is the same for neutral isotopes of one element. Their different masses affect physical processes, including diffusion, and produce separate peaks in a mass spectrum.
A mass spectrometer turns particles into ions, separates them by mass-to-charge ratio, and detects their relative abundance. A peak at a particular value is evidence for ions of a particular isotope or molecular fragment; peak height or area represents relative abundance, not necessarily a count of atoms in one molecule.
8.Calculate a weighted mean relative atomic mass
A sample with more of a heavy isotope has a larger . Multiply each isotopic mass by its fractional abundance, add the contributions, and round only at the end. When abundances are percentages, either divide each by 100 first or divide the final sum by 100.
The result should lie between the lightest and heaviest isotopic masses and closer to the more abundant isotope. That simple estimate is a powerful error check before committing to a final answer.
9.Explain atomic radius with attraction and distance
Across a period, atomic radius generally decreases. Proton number rises while added electrons enter the same principal shell, so shielding changes little and the stronger nuclear attraction pulls the outer electrons closer. Down a group, radius increases because an additional occupied shell places the outer electrons farther from the nucleus and increases shielding.
Do not describe radius as depending only on proton number. A large nuclear charge can be outweighed by extra shells and shielding. Compare species fairly: a set of isoelectronic ions has the same number of electrons, so the species with more protons is smaller because the same electron cloud is pulled in more strongly.
| Comparison | Dominant explanation |
|---|---|
| Across a period | Nuclear charge increases while added electrons enter the same shell; stronger attraction gives a smaller atom. |
| Down a group | An extra occupied shell and greater shielding place the outer electrons farther from the nucleus. |
| Cation compared with its atom | Electron loss reduces electron-electron repulsion and may remove the outer shell, so the cation is smaller. |
| Anion compared with its atom | Electron gain increases electron-electron repulsion while nuclear charge is unchanged, so the anion is larger. |
| Isoelectronic ions | More protons pull the same number of electrons closer, producing the smaller ion. |
10.Worked example: order an isoelectronic series by radius
Place , , and in decreasing order of ionic radius. Explain your reasoning.
- 1Each ion contains 18 electrons, so the ions are isoelectronic. Their electron clouds can be compared directly.
- 2The proton numbers are 16, 17, 19 and 20 respectively. Moving from to increases nuclear charge.
- 3More protons attract the same number of electrons more strongly, pulling the electron cloud closer to the nucleus.
- 4Therefore the decreasing-radius order is .
11.Use mass-spectral evidence quantitatively
A mass spectrum is more than a list of isotope masses. The position of a peak gives an ion's mass-to-charge ratio, while its relative abundance gives evidence about how common that ion is in the sample. For a singly charged atomic ion, the m/z value is numerically the isotope mass. A weighted mean of the isotope masses gives the relative atomic mass printed in a Periodic Table; it is not the mass of any one atom.
The same logic extends to molecules. A diatomic molecule made from two isotopes produces more than one molecular-ion peak because different isotope pairings are possible. For chlorine, the 35Cl–35Cl, 35Cl–37Cl, and 37Cl–37Cl combinations give an approximately 9:6:1 cluster. The middle peak is twice as likely as either mixed ordering because the two atoms can occupy either position.
12.Worked example 1: Count particles in a chloride ion
State the numbers of protons, neutrons and electrons in .
- 1The lower number, 17, is the proton number, so there are 17 protons.
- 2number − proton number = .
- 3The charge means one extra electron compared with the neutral atom: electrons.
- 4Report all three quantities with their particle names, not as an unlabelled list.
13.Worked example 2: Find relative atomic mass from isotopic abundance
An element has isotopes of mass 63.0 (69.2%) and 65.0 (30.8%). Calculate its .
- 1Use a weighted mean: .
- 2Calculate the numerator: .
- 3Divide by 100 to obtain .
- 4Give an appropriate rounded value, , which is closer to 63.0 because that isotope is more abundant.
14.Worked example 3: Chlorine is 75% ³⁵Cl and 25% ³⁷Cl. Predict the relative abundances of the molecular ions Cl₂⁺ at m/z 70, 72 and 74.
Chlorine is 75% ³⁵Cl and 25% ³⁷Cl. Predict the relative abundances of the molecular ions Cl₂⁺ at m/z 70, 72 and 74.
- 1The 70 ion is ³⁵Cl–³⁵Cl, so its probability is .
- 2The 72 ion can be formed in two ways, ³⁵Cl–³⁷Cl or ³⁷Cl–³⁵Cl, so its probability is .
- 3The 74 ion is ³⁷Cl–³⁷Cl, so its probability is .
- 4Divide by the smallest value: 0.5625 : 0.375 : 0.0625 = 9 : 6 : 1.
15.Worked example: explain beams in an electric field
Beams of protons, neutrons and electrons travel at the same speed between parallel plates. The upper plate is positive and the lower plate is negative. Describe the path of each beam and explain why the electron path is the most curved.
- 1The neutron has no charge, so it is not attracted to either plate and continues in a straight line.
- 2The proton is positive, so it curves downwards towards the negative plate.
- 3The electron is negative, so it curves upwards towards the positive plate: this is the opposite direction to the proton.
- 4The electron and proton have equal charge magnitude, but the electron has much less mass. Its charge-to-mass ratio is therefore much larger, so its acceleration and curvature are much greater.
16.Extended worked case: apply and evaluate
An element has isotopes of mass 35 (75%) and 37 (25%). Estimate its relative atomic mass.
- 1
Convert percentages to fractions: 0.75 and 0.25.
- 2
Weighted mean is .
- 3
The result lies between the isotope masses and closer to 35 because that isotope is more abundant.
Do not average 35 and 37 unweighted; the abundances are unequal.
17.Interpreting isotope evidence from mass-spectral data
A spectrum is experimental evidence for isotopic composition. Treat the supplied peak data as measurements: identify the peaks, use their relative heights or areas, and state the conclusion with suitable precision.
- 1IdentifyStage 1Record each isotope's value and its relative abundance, checking whether ions are singly charged.
- 2CalculateStage 2Use the abundance-weighted mean, retaining guard figures until the final result.
- 3EvaluateStage 3Check that the calculated value lies between the isotope masses and compare it with the tabulated value.
18.Connections, patterns and applications
19.Exam method: decode any nuclide before calculating
A short, labelled inventory prevents the most common ion and isotope errors.
- 1ReadStage 1Extract , and any ionic charge.
- 2CalculateStage 2Find protons, then neutrons, then electrons separately.
- 3Sense-checkStage 3Only electrons should differ between an atom and its ion; must lie within the isotope range.
20.Common misconceptions
- Using mass number as the number of neutrons instead of subtracting proton number.
- Changing proton number when an atom becomes an ion.
- Calling a weighted mean an isotope mass, or averaging isotope masses without abundance weights.
21.Exam focus and retrieval
- Use the terms proton number and mass number rather than vague phrases such as atomic number at the top.
- For a radius trend, state both the factor that changes and how it changes electrostatic attraction.
- Include units or percentage treatment clearly in abundance calculations.
- 1What remains unchanged when becomes ?
- 2Why does chlorine have a non-integer periodic-table mass?
- 3Which is smaller: or , and why?
22.Summary
- Proton number identifies an element; mass number counts protons and neutrons in one isotope.
- Ionic charge arises from electron transfer only.
- Relative atomic mass is an abundance-weighted mean.
- Atomic radius reflects nuclear attraction, shielding and outer-electron distance.
- Build a quantitative model of the atom, including subatomic particles, atomic and ionic radius, isotopes, and nuclide notation.
23.Curriculum alignment and applied reasoning
This extension turns the lesson into an exam-ready sequence: identify the evidence, apply the mechanism or calculation, then state a qualified conclusion. Core outcomes revisited here include: Describe the relative charge, relative mass and location of protons, neutrons and electrons in an atom.; Use atomic number, mass number, nuclide notation and ionic charge to determine the numbers of protons, neutrons and electrons in atoms and ions.; Define isotopes and explain why isotopes of an element have the same chemical properties but different masses and densities..
| Course | Mapped focus in this lesson |
|---|---|
| Cambridge International A Level Chemistry 9701 | 1.1 Particles in the atom and atomic radius 1.2 Isotopes |
| Edexcel IAL Chemistry | Sub-atomic particles, isotopes and atomic notation (2.1–2.5) Mass spectrometry (2.6–2.7) Ionisation energies and evidence for shells and sub-shells (2.8, 2.10–2.11) Orbitals and electronic configuration (2.9, 2.12–2.16) Periodicity of physical properties (2.17–2.18) 3A Ionic bonding |
| AQA International A-level Chemistry | 1.1 Atomic structure (International AS) |
| AP Chemistry | 1.2 Mass Spectra of Elements 1.7 Periodic Trends |
Scenario: An element has isotopes of mass 63 (69%) and 65 (31%). Calculate its relative atomic mass and explain why an individual atom does not have that fractional mass.
Worked reasoning: Weighted mean:
Worked reasoning: . The value is a population-weighted average; each atom is one isotope with its own isotopic mass.
Exam-quality communication: Use abundance as a weighting and distinguish relative atomic mass from mass number.
- Name the observation, quantity, structure or variable before interpreting it.
- Show the causal step or calculation route; do not jump from data to a conclusion.
- State a limitation, condition or comparison whenever the evidence cannot justify an absolute claim.