1.Lesson overview

Syllabus focus
Cambridge IAL syllabus reference
  • 1.3 Electrons, energy levels and atomic orbitals
  • 1.4 Ionisation energy
Edexcel IAL syllabus reference
  • Ionisation energies and evidence for shells and sub-shells (2.8, 2.10–2.11)
  • Orbitals and electronic configuration (2.9, 2.12–2.16)
  • Periodicity of physical properties (2.17–2.18)
AQA IAL syllabus reference
  • 1.1 Atomic structure (International AS)
AP Chemistry syllabus reference
  • 1.5 Atomic Structure and Electron Configuration
  • 1.6 Photoelectron Spectroscopy
  • 1.7 Periodic Trends
  • 3.12 Properties of Photons
By the end of this lesson you should be able to
  • Distinguish shells, subshells and orbitals, including the capacities and shapes of s and p orbitals.
  • Write electronic configurations and electron-in-boxes diagrams for atoms and ions, using s, p and d notation and the correct order of filling.
  • Explain how ions form by adding or removing electrons from the appropriate outer subshell.
  • Define first and successive ionisation energies and state that ionisation is endothermic.
  • Explain trends and anomalies in first ionisation energies using nuclear charge, distance, shielding and subshell or electron-pair repulsion.
  • Use successive-ionisation-energy data to infer shell structure and the likely group of an element.
  • Relate photon energy to absorption or emission during an electronic transition in an atom or molecule.

Electronic structure makes the periodic table intelligible. Orbitals provide an economical model for where electrons are likely to be found, while ionisation-energy evidence reveals shell structure, subshells and the strength of attraction between a nucleus and its electrons.

How this chapter fits together

Build configurations from shells, subshells and orbitals; account for electron removal in ions; then interpret first and successive ionisation energies as evidence for attraction, shielding and electronic structure.

2.Key language and ideas

Use these definitions precisely
Principal quantum shell
A main energy level of electrons around a nucleus, numbered 1, 2, 3 and so on.
Subshell
A set of orbitals within a shell of similar energy, labelled , or .
Orbital
A region of space around a nucleus that can hold a maximum of two electrons with opposite spins.
First ionisation energy
The energy needed to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous ions.
Shielding
Reduction of nuclear attraction on an outer electron caused by repulsion from inner-shell electrons.
Successive ionisation energies
Energies required to remove electrons one at a time from gaseous ions of the same element.

3.Use the hierarchy: shell, subshell, orbital, electron

A shell contains one or more subshells; a subshell contains orbitals; an orbital holds at most two electrons of opposite spin. The subshell has one orbital and holds two electrons, has three orbitals and holds six, and has five orbitals and holds ten.

Orbitals are probability regions, not fixed circular paths. At this level, describe an orbital as spherical and a orbital as two-lobed. The models explain why electrons occupy distinct energy levels and why energy is needed to remove them.

Three panels: an s orbital as one sphere, a p orbital as two opposite-phase lobes with a node at the nucleus, and a d orbital as four lobes on the diagonals, each labelled with how many orbitals of that type a shell holds.
Figure 1: The shape of an orbital fixes how many orientations it can take, and so how many orbitals of that type a shell holds.

4.Successive ionisation energies reveal shells

First ionisation energy is the energy needed to remove one electron from each gaseous atom in a mole of atoms, producing gaseous 1+ ions. Successive ionisations remove electrons from increasingly positive ions and therefore generally require more energy. A very large jump marks removal from a lower principal shell after outer electrons are gone. Across a period, nuclear charge, shielding and subshell structure all matter; trends need an explanation rather than a blanket claim of smooth increase.

5.Write configurations and electron-in-boxes logically

Fill lower-energy subshells first and use the capacities , and . In electron-in-box notation, place one electron in each equal-energy orbital before pairing them. This minimises electron repulsion and reflects the observed electronic structures.

For elements through krypton, a configuration such as communicates both shell and subshell occupancy. The outer configuration predicts many chemical properties, so it is more useful than a simple shell notation when explaining periodicity.

Subshell capacities

6.Form ions by removing the correct outer electrons

Cations form when atoms lose electrons; anions form when atoms gain them. For main-group atoms, add or remove electrons from the outermost occupied shell. For transition-metal ions, remove the electrons before the electrons because the electrons become higher in energy once the atom has electrons in the subshell.

Always write the neutral-atom configuration first, then adjust the electron count. The ion's configuration must contain the correct total number of electrons and should be consistent with its stated charge.

7.Define and explain first ionisation energy

The first ionisation-energy equation must show gaseous atoms and gaseous singly charged ions: . Ionisation is always endothermic because energy is needed to overcome the attraction between a negative electron and the positive nucleus.

First ionisation energy rises across a period overall because nuclear charge rises while electrons enter the same shell. It falls down a group because increased distance and shielding more than offset the increased nuclear charge. A complete explanation names the changing factor and links it to attraction on the electron removed.

8.Read anomalies and large jumps as structural evidence

Small dips in the across-period trend are meaningful. Removing a electron from boron needs less energy than removing a electron from beryllium because the electron is higher in energy. Oxygen has a lower first ionisation energy than nitrogen because pairing in one orbital increases electron-electron repulsion.

A very large jump between successive ionisation energies shows that all outer-shell electrons have been removed and the next electron comes from an inner shell. The number of electrons removed before the jump therefore identifies the number of valence electrons and often the main group.

The eleven successive ionisation energies of sodium on a logarithmic axis, with dashed lines at the two large jumps splitting the points into groups of one, eight and two.
Figure 2: Each large jump marks a shell boundary, so groups of one, eight and two points read from the outside in give the structure 2,8,1.
Factors controlling ionisation energy
FactorEffect on removal
Greater nuclear chargeStronger attraction; ionisation energy increases.
Greater distanceWeaker attraction; ionisation energy decreases.
More shieldingWeaker effective attraction; ionisation energy decreases.
Higher-energy subshell or paired electronElectron is easier to remove; a local dip can occur.

9.Use successive ionisation energies as structural evidence

Successive ionisation energies are not just a sequence of numbers; they are a record of the changing attraction experienced by each electron removed. The first electron is removed from a neutral atom, the second from a +1 ion, and so on. Each removal makes the remaining electrons more strongly attracted to the nucleus, so successive values generally increase.

A very large jump identifies the point at which removal begins from an inner shell. The number of electrons removed before the jump is therefore the number of outer-shell electrons. Within a shell, a smaller irregularity can arise when removal changes from an s subshell to a higher-energy p subshell, or when pairing begins and electron–electron repulsion makes one electron easier to remove.

A disciplined way to think about it
Explain an ionisation-energy graph with a causal chain: nuclear charge, distance, shielding, subshell energy and spin-pair repulsion.
Photoelectron spectra: evidence for electron energy

Photoelectron spectroscopy (PES) removes electrons from gaseous atoms using photons of known energy. The kinetic energy of each emitted electron is measured, so photon energy equals binding energy plus kinetic energy. A larger binding energy means that an electron was held more strongly by the nucleus.

Each peak represents electrons in a subshell. Peak area or relative height is proportional to the number of electrons in that subshell, while the binding-energy position reveals its energy and attraction. Core-electron peaks lie at high binding energy; valence-electron peaks are easier to remove. PES therefore supplies experimental evidence for shells, subshells and electron configurations rather than merely illustrating a diagram.

When comparing elements, a shift of a comparable subshell to higher binding energy indicates stronger attraction, often because nuclear charge has increased without a compensating increase in shielding. Read the axis carefully: some spectra plot binding energy in the reverse direction, but the chemical conclusion still depends on which electrons need more energy to remove.

Absorption, emission and photon energy

An electron can absorb a photon only when the photon's energy matches the gap to an available higher energy level. When an excited electron falls to a lower level, it emits a photon with that same energy difference. The relationship is , so a larger energy gap gives a higher-frequency photon and a shorter wavelength.

Electronic transitions commonly involve ultraviolet or visible radiation; infrared absorption instead usually changes molecular vibration. This distinction lets a spectrum provide evidence about the type of transition rather than merely showing that a sample absorbed radiation.

10.Worked example 1: Write a transition-metal ion configuration

Question

Write the electron configuration of , given .

Step-by-step solution
  1. 1
    Write neutral iron first: .
  2. 2
    Form a ion by removing two electrons.
  3. 3
    For a transition metal, remove the electrons before electrons.
  4. 4
    Therefore is , or .
Where the marks are won
The crucial chemical decision is removal from , not removal of two electrons.

11.Worked example 2: Use a successive-ionisation jump

Question

An element has a very large jump between its fifth and sixth ionisation energies. What does this show about its outer-shell electron arrangement?

Step-by-step solution
  1. 1
    The first five electrons removed are comparatively easier to remove, so they are in the outer shell.
  2. 2
    The sixth electron is much more strongly attracted because it is in an inner shell.
  3. 3
    The atom therefore has five outer-shell electrons.
  4. 4
    It belongs to the group with five valence electrons in the relevant main-group numbering system.
Where the marks are won
Explain the jump by a change of shell, not simply by saying that the energy gets larger.

12.Worked example 3: The successive ionisation energies of an element are 590, 1145, 4912, 6473 and 8154 kJ mol⁻¹. What group is the element in, and why

Question

The successive ionisation energies of an element are 590, 1145, 4912, 6473 and 8154 kJ mol⁻¹. What group is the element in, and why?

Step-by-step solution
  1. 1
    The first two values increase moderately, showing that the first two electrons are removed from the same outer shell.
  2. 2
    The jump from the second to the third value is large, so the third electron is removed from an inner shell.
  3. 3
    Two electrons were removed before the jump; the atom therefore has two outer-shell electrons.
  4. 4
    The element is in Group 2, assuming it is a main-group element in the stated range.
What the method shows
The decisive evidence is the position of the large jump, not simply the absolute size of the first ionisation energy.

13.Extended worked case: apply and evaluate

Problem

Successive ionisation energies show a dramatic jump between the second and third removals. What does this suggest about the atom?

Reasoned solution
  1. 1

    The first two electrons are removed from the outer shell at comparatively lower energies.

  2. 2

    The third would be removed from an inner shell closer to the nucleus and more strongly attracted.

  3. 3

    The atom therefore likely has two outer-shell electrons and belongs to Group 2 in the simple main-group model.

Check or limitation

A jump identifies shell occupancy, not the precise element without additional data.

14.Using ionisation-energy and spectral evidence

Tables and graphs of successive ionisation energies or line spectra can be treated as experimental evidence for shells and subshells. The quality of the conclusion depends on recognising scale changes and comparing like with like.

Using ionisation-energy and spectral evidence
  1. 1
    Plot or inspect
    Stage 1
    Use a clear scale, identify the overall trend, then mark anomalous points or a large discontinuity.
  2. 2
    Interpret
    Stage 2
    Relate a gradual trend to nuclear charge, distance and shielding; relate a large jump to a different shell.
  3. 3
    Justify
    Stage 3
    State which electron or subshell is being removed and why its energy differs.
Safety and quality
For flame or discharge-tube demonstrations, use eye protection, avoid looking directly at intense sources and follow the teacher's electrical-safety procedure.

15.Connections, patterns and applications

Think beyond this page
To periodicity
Electronic configuration explains repeating chemical behaviour and the block structure of the periodic table.
To transition metals
The relative energies of and electrons explain variable ions and later complex-ion chemistry.

16.Exam method: explain a trend with a causal chain

A trend explanation needs more than naming a factor: show how it changes the attraction between nucleus and electron.

A reliable exam method
  1. 1
    Locate
    Stage 1
    State whether the comparison is across a period, down a group or between subshells.
  2. 2
    Identify
    Stage 2
    Name the relevant changes in nuclear charge, shielding, distance or electron pairing.
  3. 3
    Conclude
    Stage 3
    Link them to stronger or weaker attraction and then to a higher or lower ionisation energy.

17.Common misconceptions

Avoid these errors
  • Saying an orbital holds one electron rather than up to two with opposite spins.
  • Removing electrons before electrons when forming common transition-metal cations.
  • Explaining an ionisation-energy dip with atomic radius alone while ignoring subshell energy or pairing.

18.Exam focus and retrieval

How to earn clear, accurate marks
  • Include in an ionisation-energy equation.
  • Use the word overall for a periodic trend, then account for named anomalies.
  • On a graph, distinguish a large jump from an ordinary increase.
Quick checks — answer without looking back
  1. 1
    How many orbitals are in a subshell?
  2. 2
    Why is first ionisation always endothermic?
  3. 3
    What does a jump after the second successive ionisation energy imply?

19.Summary

What to carry forward
  • Shells contain subshells, which contain orbitals of maximum occupancy two.
  • Configurations and outer electrons underpin chemical periodicity.
  • Ionisation energy reflects nuclear charge, shielding, distance, subshell energy and electron pairing.
  • Successive-ionisation jumps reveal the number of outer-shell electrons.
I can now…
  • Explain electronic configurations, orbitals, shielding and inter-electron repulsion, then apply them to ionisation-energy evidence.
Atom Builder & Electron StructureOpen full screen

20.Curriculum alignment and applied reasoning

Detailed-note focus

This extension turns the lesson into an exam-ready sequence: identify the evidence, apply the mechanism or calculation, then state a qualified conclusion. Core outcomes revisited here include: Distinguish shells, subshells and orbitals, including the capacities and shapes of s and p orbitals.; Write electronic configurations and electron-in-boxes diagrams for atoms and ions, using s, p and d notation and the correct order of filling.; Explain how ions form by adding or removing electrons from the appropriate outer subshell..

Cross-course alignment
Where this lesson transfers
CourseMapped focus in this lesson
Cambridge International A Level Chemistry 97011.3 Electrons, energy levels and atomic orbitals
1.4 Ionisation energy
Edexcel IAL ChemistryIonisation energies and evidence for shells and sub-shells (2.8, 2.10–2.11)
Orbitals and electronic configuration (2.9, 2.12–2.16)
Periodicity of physical properties (2.17–2.18)
AQA International A-level Chemistry1.1 Atomic structure (International AS)
AP Chemistry1.5 Atomic Structure and Electron Configuration
1.6 Photoelectron Spectroscopy
1.7 Periodic Trends
3.12 Properties of Photons
Applied analysis: Explaining an ionisation-energy anomaly

Scenario: A first-ionisation-energy graph rises across a period but contains a small fall. Explain how sub-shell energy or paired-electron repulsion can cause this without rejecting the overall trend.

Worked reasoning: Across a period, nuclear charge rises with similar shielding, so attraction for the outer electron generally increases. A first electron in a higher-energy p sub-shell or repulsion between paired electrons can make removal easier at a particular element, producing a local fall.

Exam-quality communication: Refer to attraction, distance and shielding before explaining the exception.

Precision audit
  • Name the observation, quantity, structure or variable before interpreting it.
  • Show the causal step or calculation route; do not jump from data to a conclusion.
  • State a limitation, condition or comparison whenever the evidence cannot justify an absolute claim.