February/March 2026 Paper 52

2026 · 2 questions · 27 parts · 30 marks

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Context for question 2
Blood plasma contains a number of different cations. Many of these cations emit a different colour of light when placed in a flame. Flame emission photometry is a method of determining the concentration of cations in a sample using the intensity of light emitted. In an experiment, a sample of blood plasma is placed into a colourless flame. K ions in the blood plasma absorb energy from the flame and emit light with a lilac colour. The intensity of the light emitted is measured. To determine the concentration of K ions in the sample, a calibration graph showing the relationship between known concentration of K ions and light intensity is required.
Context for 2(a)
A solution of potassium chloride, KCl(aq), is prepared. The concentration of aqueous potassium ions, K, in this solution is 0.100 g dm. Different volumes of the solution of KCl(aq) are taken and diluted by adding specific volumes of distilled water to prepare solutions of specific concentrations. Each prepared solution of known [K(aq)] is tested using flame emission photometry. Table 2.1 shows the relative light intensity measured for each prepared solution.
2(a)(i)Concentration Solutions Titration CalculationsEasy1 mark
Complete Table 2.1 to show the volume of distilled water added to make each prepared solution of known [K(aq)].
volume of KCl(aq) / cmvolume of distilled water added / cm[K(aq)] / g dmrelative light intensity
0.0050.000.0
0.50
2.1
1.00
4.2
1.50
6.7
2.00
8.8
2.50
11.0
3.00
11.2
3.50
15.7
4.00
17.1
4.50
17.1
5.00
17.1
2(a)(ii)Practical Techniques SafetyEasy1 mark
Identify a suitable piece of apparatus for adding the distilled water.
2(a)(iii)Experimental PlanningEasy1 mark
Identify the dependent variable in this experiment.
2(a)(iv)Tables Graphs Data AnalysisMedium2 marks
Plot a calibration graph on the grid in Figure 2.1 to show the relationship between [K(aq)] and relative light intensity. Use a cross () to plot each data point. Draw one line of best fit for [K(aq)] from to g dm. Draw a second line of best fit for [K(aq)] from to g dm. Extend both lines so they meet.
Diagram to annotate
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Draw with the mouse or a finger.
2(a)(v)Tables Graphs Data AnalysisEasy1 mark
Describe how the graph shows that [K(aq)] from to g dm is directly proportional to relative light intensity.
2(a)(vi)Tables Graphs Data AnalysisMedium1 mark
Circle the most anomalous point on your graph in Figure 2.1. Suggest one reason to explain the anomalous point you have circled.
Diagram to annotate
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Draw with the mouse or a finger.
2(b)(i)Tables Graphs Data AnalysisEasy1 mark
A sample of blood plasma is diluted 100 times and tested using flame emission photometry. The relative light intensity recorded is 3.8. Use your graph in Figure 2.1 to determine the [K(aq)], in g dm, in the sample.
[K(aq)] in diluted blood plasma
2(b)(ii)Tables Graphs Data AnalysisMedium1 mark
The healthy range for [K(aq)] in blood plasma is between 0.100 and 0.200 g dm. State whether the sample of blood plasma tested in 2(b)(i) is within the healthy range, too high or too low. Explain your answer.
Classification and explanation
0 words
2(b)(iii)Uv Visible SpectroscopyMedium1 mark
When testing samples of blood plasma, a coloured light filter needs to be used which only allows lilac-coloured light emitted from the sample to reach the detector. Suggest why this coloured light filter is needed when testing blood plasma but is not necessary when testing KCl(aq).
2(c)Tables Graphs Data AnalysisMedium1 mark
Explain why flame emission photometry is not suitable for measuring [K(aq)] at g dm and above.
2(d)Uncertainty Errors EvaluationMedium1 mark
State whether the data used for the calibration graph in Figure 2.1 is reliable. Explain your answer.