Solution B is 100 cm3 of an aqueous solution containing 0.450 mol dm−3 CH3CH2CH2COOH. Solution C is 200 cm3 of an aqueous solution containing sodium butanoate, CH3CH2CH2COONa.
B is added to C to produce 300 cm3 of solution D. The concentration of H+ ions in D is 6.31×10−5 mol dm−3.
Calculate the concentration of CH3CH2CH2COONa in C.
(If you were unable to calculate an answer in part (b)(ii), use 3.00×10−5 as the value of Ka of CH3CH2CH2COOH. This is not the correct answer.)