It is given that ∫a2a41e2x(2+e−x)dx=50, where a is a positive constant.
7(a)Antiderivatives Definite IntegralsHard5 marks
Show that a=41ln(200+ea).
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7(b)Root Finding IterationMedium2 marks
Show by calculation that the value of a lies between 1.0 and 1.5.
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7(c)Root Finding IterationMedium3 marks
Use an iterative formula, based on the equation in part (a), to find the value of a correct to 4 significant figures. Give the result of each iteration to 6 significant figures.