May/June 2026 Paper 33

2026 · 26 questions · 49 parts · 80 marks

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Finish set
Q1
1
–/1 mk
Q2
2
–/2 mks
Q3
3(a)3(b)
–/2 mks
Q4
4
–/2 mks
Q5
5(a)5(b)
–/2 mks
Q6
6
–/2 mks
Q7
7
–/2 mks
Q8
8(a)8(b)8(c)
–/5 mks
Q9
9(a)9(b)9(c)
–/5 mks
Q10
10
–/1 mk
Q11
11(a)(i)11(a)(ii)11(b)(i)11(b)(ii)11(b)(iii)11(b)(iv)
–/7 mks
Q12
12
–/2 mks
Q13
13(a)13(b)
–/4 mks
Q14
14
–/1 mk
Q15
15(a)15(b)15(c)(i)15(c)(ii)
–/6 mks
Q16
16
–/2 mks
Q17
17
–/3 mks
Q18
18
–/3 mks
Q19
19
–/2 mks
Q20
20(a)20(b)
–/4 mks
Q21
21(a)21(b)
–/3 mks
Q22
22(a)22(b)(i)22(b)(ii)22(b)(iii)
–/5 mks
Q23
23
–/2 mks
Q24
24(a)24(b)
–/3 mks
Q25
25(a)25(b)25(c)
–/5 mks
Q26
26
–/4 mks
20(a)Probability Tree Diagrams Conditional ProbabilityEasy2 marks
Fair six-sided spinner in the shape of a regular hexagon with sections numbered 1 to 6 and the arrow pointing into section 5
The diagram shows a fair spinner. Azra spins the spinner twice.
Complete the tree diagram.
Tree diagram for two spins: the first-spin branch 'lands on 5' is labelled 1/6, the branch 'does not land on 5' has a blank label; from each first-spin outcome two second-spin branches, 'lands on 5' and 'does not land on 5', have blank labels
First spin, does not land on 5
After landing on 5: second spin lands on 5
After landing on 5: second spin does not land on 5
After not landing on 5: second spin lands on 5
After not landing on 5: second spin does not land on 5
20(b)Probability Tree Diagrams Conditional ProbabilityEasy2 marks
Find the probability the spinner lands on 5 both times.

Answer