1aEasy1 markA horizontal section on a distance–time graph shows that the object is:AAcceleratingBStationaryCMoving at constant speedDReversingGrade answerGrading criteria
1bMedium1 markA cyclist travels 150 m in 12 s. The average speed is ____ m/s.AnswerGrade answerGrading criteria
2aHard3 marksCreate a clear annotated answer on the canvas. Use a diagram, graph, flowchart, equation layout and/or concise labels to show your reasoning.Describe the motion of a falling object before and after it reaches terminal velocity.PenEraserUndoRedoClearDraw with the mouse or a finger.Grade answerGrading criteria
2bEasy1 markDefine speed.ASpeed in a stated direction; it is a vectorBSpeedCDistance travelled per unit time: v=s/tDDistance travelledGrade answerGrading criteria
3aEasy1 markDefine velocity.ADistance travelled per unit time: v=s/tBSpeed in a stated direction; it is a vectorCSpeedDDistance travelledGrade answerGrading criteria
4aEasy1 markWhat is the gradient of a distance–time graph?ASpeedBDistance travelled per unit time: v=s/tCSpeed in a stated direction; it is a vectorDDistance travelledGrade answerGrading criteria
4bEasy1 markWhat is the area under a speed–time graph?ADistance travelled per unit time: v=s/tBSpeed in a stated direction; it is a vectorCSpeedDDistance travelledGrade answerGrading criteria
5aEasy1 markWhat is terminal velocity?ADistance travelled per unit time: v=s/tBSpeed in a stated direction; it is a vectorCThe constant speed reached when drag balances weight, so resultant force and acceleration are zeroDSpeedGrade answerGrading criteria
6aMedium1 markUse the lesson knowledge to answer precisely: Define speed.ASpeed in a stated direction; it is a vectorBDistance travelled per unit time: v=s/tCSpeedDDistance travelledGrade answerGrading criteria
6bMedium1 markUse the lesson knowledge to answer precisely: Define velocity.ADistance travelled per unit time: v=s/tBSpeedCDistance travelledDSpeed in a stated direction; it is a vectorGrade answerGrading criteria
7aMedium1 markA cyclist starting from rest accelerates at a constant 2.0 m/s² over a distance of 25 m. Calculate the final speed in m/s.AnswerGrade answerGrading criteria
7bEasy1 markWhich equation should be used to find the final speed of a uniformly accelerating object when the distance travelled is known but the time is not?Aa=Δv/ΔtBv² = u² + 2asCv=s/tDaverage speed = total distance/total timeGrade answerGrading criteria