May/June 2026 Paper 11

2026 · 40 questions · 40 parts · 40 marks

0/40 marks
0Correct0Partial0Wrong40Unattempted
Filters0 active

Questions

Select a part to jump to its question

Finish set
Q1
1
–/1 mk
Q2
2
–/1 mk
Q3
3
–/1 mk
Q4
4
–/1 mk
Q5
5
–/1 mk
Q6
6
–/1 mk
Q7
7
–/1 mk
Q8
8
–/1 mk
Q9
9
–/1 mk
Q10
10
–/1 mk
Q11
11
–/1 mk
Q12
12
–/1 mk
Q13
13
–/1 mk
Q14
14
–/1 mk
Q15
15
–/1 mk
Q16
16
–/1 mk
Q17
17
–/1 mk
Q18
18
–/1 mk
Q19
19
–/1 mk
Q20
20
–/1 mk
Q21
21
–/1 mk
Q22
22
–/1 mk
Q23
23
–/1 mk
Q24
24
–/1 mk
Q25
25
–/1 mk
Q26
26
–/1 mk
Q27
27
–/1 mk
Q28
28
–/1 mk
Q29
29
–/1 mk
Q30
30
–/1 mk
Q31
31
–/1 mk
Q32
32
–/1 mk
Q33
33
–/1 mk
Q34
34
–/1 mk
Q35
35
–/1 mk
Q36
36
–/1 mk
Q37
37
–/1 mk
Q38
38
–/1 mk
Q39
39
–/1 mk
Q40
40
–/1 mk
25Structural Geometric IsomerismHard1 mark
The formula of 11-cis-retinal is CHO. The structure of 11-cis-retinal consists of a cyclohexene ring and a long aliphatic side chain ending in an aldehyde group. The long aliphatic side chain contains one or more bonds. One bond is between carbons numbered 11 and 12. The arrangement is cis at this point. Which row is correct?
Table of rows A to D: the left column gives the total number of C=C double bonds in 11-cis-retinal (5 for rows A and B, 6 for rows C and D); the right column draws the arrangement around carbons 11 and 12 as R1-C=C-R2 with attached H atoms -- rows A and C show R1 and R2 both on the upper side and both H atoms on the lower side (the cis arrangement); rows B and D show R1 upper-left and R2 lower-right with the two H atoms on the opposite corners (the trans arrangement).