May/June 2026 Paper 23

2026 · 5 questions · 32 parts · 60 marks

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4(a)(i)AlcoholsMedium2 marks
The structure of compound V is shown in Figure 4.1.
Figure 4.1, the skeletal structure of compound V: a central carbon bonded to CH$_3$, an OH group, a CH$_2$OH group and a CH(OH)CH$_2$OH branch, i.e. (CH$_3$)(OH)C(CH$_2$OH)CH(OH)CH$_2$OH
Complete Table 4.1.
primary hydroxy groupssecondary hydroxy groupstertiary hydroxy groups
number of groups in one molecule of V
4(a)(ii)Organic Functional Group TestsMedium2 marks
Complete Table 4.2 to show what is observed when separate samples of V are added to each reagent. State 'none' if no reaction occurs.
ReagentObservation with V
2,4-dinitrophenylhydrazine (2,4-DNPH)
Fehling's reagentnone
4(a)(iii)Organic Functional Group TestsHard1 mark
Suggest why Fehling's reagent does not react with V but does react with aldehyde functional groups.

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4(b)(i)AlcoholsEasy1 mark
Figure 4.1 is repeated for use in 4(b).
Figure 4.1, the skeletal structure of compound V: a central carbon bonded to CH$_3$, an OH group, a CH$_2$OH group and a CH(OH)CH$_2$OH branch, i.e. (CH$_3$)(OH)C(CH$_2$OH)CH(OH)CH$_2$OH (repeated for use in 4(b))
V is completely oxidised by heating under reflux with an excess of acidified to produce organic compound Z.
Describe the colour change in this reaction.
Colour of the mixture at the start of the reaction, and after the reaction
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4(b)(ii)AlcoholsHard1 mark
Draw the structure of Z.
PenEraserUndoRedoClear
Draw with the mouse or a finger.
4(c)(i)Structural Geometric IsomerismEasy2 marks
Compounds W, X and Y are structural isomers of V.
Figure 4.2, the skeletal structures of the four structural isomers of V, labelled V, W, X and Y: V is (CH$_3$)(OH)C(CH$_2$OH)CH(OH)CH$_2$OH (a CH$_3$ and an OH on the same carbon, a CH$_2$OH branch, and a CH(OH)CH$_2$OH chain); W is HOCH(CH$_2$CH$_2$OH)CH(OH)CH$_2$OH (two carbons each bearing an OH, one carrying a CH$_2$CH$_2$OH branch, the other a CH$_2$OH branch); X is a central carbon bonded to an OH, two separate CH$_2$OH groups and a CH$_2$CH$_2$OH branch; Y is a central carbon bonded to four CH$_2$OH groups (fully symmetric, no CH$_3$ and no direct OH on the central carbon)
Describe structural isomerism.

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4(c)(ii)Optical IsomerismHard2 marks
Identify which of structures V, W, X and Y show stereoisomerism. Explain your answer by referring to the relevant parts of the molecule that cause stereoisomerism.

Answer

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4(c)(iii)Carboxylic Acids EstersHard1 mark
Y reacts with reagent R to produce compound E.
Figure 4.3, the reaction of isomer Y with reagent R to give compound E: Y is the symmetric central carbon with four CH$_2$OH arms, and E is the same central carbon with all four arms now esterified as -CH$_2$-O-CHO (a formate ester group, C(=O)H, on each arm)
Name reagent R.
4(d)(i)AlcoholsHard1 mark
Exactly of one of the isomers, V, W, X or Y, is completely oxidised by of acidified to produce only one organic compound with molecular formula .
Identify which isomer, V, W, X or Y, is used in this reaction.
4(d)(ii)Oxidation Reduction Redox EquationsMedium1 mark
Complete the equation for this reaction.
The four missing coefficients, for , , and in that order, separated by commas