February/March 2026 Paper 42

2026 · 10 questions · 49 parts · 100 marks

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1(a)1(b)(i)1(b)(ii)1(b)(iii)1(c)

–/10 mks

2(a)2(b)(i)2(b)(ii)2(c)(i)2(c)(ii)2(d)2(e)

–/12 mks

–/8 mks

4(a)4(b)(i)4(b)(ii)4(b)(iii)4(c)

–/9 mks

5(a)5(b)5(c)(i)5(c)(ii)

–/7 mks

6(a)6(b)(i)6(b)(ii)6(c)(i)6(c)(ii)

–/11 mks

7(a)7(b)(i)7(b)(ii)7(c)(i)7(c)(ii)7(c)(iii)

–/10 mks

8(a)8(b)(i)8(b)(ii)8(b)(iii)

–/10 mks

9(a)9(b)(i)9(b)(ii)9(b)(iii)9(c)

–/12 mks

10(a)(i)10(a)(ii)10(b)(i)10(b)(ii)10(b)(iii)

–/11 mks

7(a)Alternating Current RectificationEasy2 marks

State what is meant by the root-mean-square (r.m.s.) value of an alternating current.

Answer

0 words

7(b)(i)Alternating Current RectificationEasy1 mark

There is a sinusoidal alternating current in a resistor of resistance

26 Ω

. The power

P

dissipated in the resistor varies with time

t

as shown in Figure 7.1.

Figure 7.1, a graph of power $P$ (in W) dissipated in the resistor against time $t$ (in s), a sine-squared curve oscillating between 0 and about 6.4 W with a period of 0.025 s, shown from $t=0$ to $t=0.05$ s

Determine the mean power dissipated in the resistor.

7(b)(ii)Alternating Current RectificationEasy2 marks

Calculate the r.m.s. current in the resistor.

7(c)(i)Alternating Current RectificationEasy1 mark

The current in the resistor in 7(b) is now half-wave rectified. State the name of the electric circuit component that is used to achieve this rectification.

7(c)(ii)Alternating Current RectificationEasy2 marks

On Figure 7.2, sketch the variation of the power

P

dissipated in the resistor between

t = 0

and

t = 0.050 s

.

Diagram to annotate

Draw with the mouse or a finger.

7(c)(iii)Alternating Current RectificationMedium2 marks

Determine the r.m.s. current in the resistor. Explain your reasoning.

Explain your reasoning

0 words