February/March 2026 Paper 42

2026 · 11 questions · 49 parts · 80 marks

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1(a)1(b)1(c)

–/6 mks

2(a)(i)2(a)(ii)2(a)(iii)2(a)(iv)2(b)2(b)(i)2(b)(ii)

–/9 mks

3(a)(i)3(a)(ii)3(a)(iii)3(b)

–/7 mks

4(a)4(b)(i)4(b)(ii)4(c)

–/7 mks

5(a)5(b)(i)5(b)(ii)

–/8 mks

6(a)(i)6(a)(ii)6(a)(iii)6(b)6(b)(i)6(b)(ii)

–/7 mks

7(a)7(b)7(c)7(d)

–/7 mks

8(a)(i)8(a)(ii)8(b)8(b)(i)8(b)(ii)

–/8 mks

9(a)9(b)9(c)

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Q10

10(a)10(a)(i)10(a)(ii)10(b)10(b)(i)10(b)(ii)

–/5 mks

Q11

11(a)11(b)11(b)(i)11(b)(ii)

–/8 mks

10(a)

Planetary nebulae form as part of the life cycle of stars.

10(a)(i)Stars Stellar EvolutionEasy1 mark

Complete the sentence about a planetary nebula. Stars expand when they run out of hydrogen to fuel nuclear reactions. A ___ forms a planetary nebula.

10(a)(ii)Stars Stellar EvolutionEasy1 mark

State what is at the centre of a planetary nebula.

10(b)

A planetary nebula emits blue light and red light at two specific wavelengths:

5.0 \times 1 0^{- 7}

m and

6.6 \times 1 0^{- 7}

10(b)(i)Electromagnetic Spectrum ApplicationsEasy1 mark

Explain why the light with a wavelength of

5.0 \times 1 0^{- 7}

m is the blue light.

Answer

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10(b)(ii)Wave Properties Wave BehaviourEasy2 marks

The speed of light in a vacuum is

3.0 \times 1 0^{8}

m/s. Calculate the frequency of the blue light.

Answer