February/March 2026 Paper 42

2026 · 11 questions · 49 parts · 80 marks

0/80 marks

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1(a)1(b)1(c)

–/6 mks

2(a)(i)2(a)(ii)2(a)(iii)2(a)(iv)2(b)2(b)(i)2(b)(ii)

–/9 mks

3(a)(i)3(a)(ii)3(a)(iii)3(b)

–/7 mks

4(a)4(b)(i)4(b)(ii)4(c)

–/7 mks

5(a)5(b)(i)5(b)(ii)

–/8 mks

6(a)(i)6(a)(ii)6(a)(iii)6(b)6(b)(i)6(b)(ii)

–/7 mks

7(a)7(b)7(c)7(d)

–/7 mks

8(a)(i)8(a)(ii)8(b)8(b)(i)8(b)(ii)

–/8 mks

9(a)9(b)9(c)

–/8 mks

Q10

10(a)10(a)(i)10(a)(ii)10(b)10(b)(i)10(b)(ii)

–/5 mks

Q11

11(a)11(b)11(b)(i)11(b)(ii)

–/8 mks

Context for question 2

Figure 2.1 shows a ship made of steel floating on the sea.

Figure 2.1, a large steel container ship loaded with stacked containers, floating on the sea

2(a)(i)Density PressureEasy1 mark

State the equation that links density, mass and volume.

2(a)(ii)Density PressureEasy1 mark

The density of steel is 7900 kg/m

^{3}

. The mass of a solid steel cube is 110 kg. Calculate the volume of the steel cube.

Answer

2(a)(iii)Upthrust BuoyancyEasy1 mark

The density of sea water is 1030 kg/m

^{3}

. State why the solid steel cube sinks when placed in sea water.

Answer

0 words

2(a)(iv)Upthrust BuoyancyMedium2 marks

Explain why the steel ship in Figure 2.1 floats on the sea water.

Answer

0 words

2(b)

The mass of the ship is

3.5 \times 1 0^{7}

kg. The ship accelerates at 0.75 m/s

^{2}

2(b)(i)Newtons LawsEasy2 marks

Calculate the force which causes this acceleration.

Answer

2(b)(ii)Friction Drag Terminal VelocityMedium2 marks

Explain why the force provided by the ship’s engine must be larger than the value in 2(b)(i).

Answer

0 words